Lmao that’s fucked up hahaha
C, if their is a requirement to show your work and random guesses that don’t show work get no credit.
Diabolical
It’s B - 50%; either correct (50%) or false (50%), binary 0/1, yes/no, score or not.
I would answer C) 0% - Ultimately I feel this isn’t a “pick the correct answer” type of test and more of a “pick the best answer” type of test.
My reasoning is there are really two questions - one is being answered at random, the other I am answering. The one being answered at random is making any answer it chooses wrong - If it picks A or D (25%), then the correct answer is B (50%). If it picks B (50%), then the answer is either A or D (25%). If it chooses C (0%) then the correct answer is A or D (25%) again. No matter which one is chosen at random, it becomes wrong as soon as it is chosen. So then back to the question on the test that I am answering, the correct answer is C) 0%.
Also, if the teacher marks that wrong, then I am even more correct.
You can’t separate the question like that. Whichever answer you circle indicates your assertion that this is the probability of getting the correct answer by uniform random chance.
This means that any answer your circle is wrong, and so the correct answer is to not circle any of them. You could even write e) none of the above to indicate that you have deliberately chosen not to circle one of them instead of skipping the question.
I have had plenty of exams with multiple choice questions that included the possibility of no correct answers, one correct answer, or even multiple correct answers, and we were expected to make that judgement (rather than blindly follow instructions).
It’s definitely B ) 50%. Ignoring the values for answers, there can only be 1 “correct” answer. If you have 4 options and 1 can be correct, a random guess is 25%. Since there are 2 options for 25%, you have a 50% chance of guessing the correct 25%.
hah I see what you did there!
Here’s a more fun one:
If you pick an answer to this question at random, what is the chance that you will be correct? Mark at least one of the applicable options.
(a) 20%
(b) 6.25%
(c) 0%
(d) 20%
And as another puzzle, what happens if you swap “at least one of the” for “all”?
Couldn’t you argue that 0% is correct?
It’s a paradox, no of the answers can be correct, so the chance that you pick the correct one is 0%.
Sure, by picking it, it makes it wrong, but you don’t care about that.
If you ran a infite monte carlo test on it, you’d end up with 0% correct answers.
Sure, picking the zero makes it not true again, but you don’t care about that - it prooves that the statistical test holds.
If you ignore self-referential nature of the question and stop the iteration at some point, sure, you can argue that any answer is correct.
If you ran a infite monte carlo test on it, you’d end up with 0% correct answers.
That would mean your Monte Carlo test is set up incorrectly because at least 1/4 of the results of the test would be the “correct” answer as per your own argument, thus invalidating it.
The trick is that there is no paradox, only the implication of one. ‘If’ being the key word - you’re not actually being asked to answer randomly, but you are being subtly trolled.
Nah it’s a paradox. There’s no such thing as just a freestanding Monte Carlo test that you can just “run” - you do actually need to define enough parameters to make it tell you anything.
This kind of self-referential stuff feels like a proof of Gödel’s incompleteness theorems with extra steps.
The correct answer is to leave all the options unmarked.
If you do pick an answer, then you didn’t do it randomly. When not marking the answers, the if-statement has the result of “false”, but that’s not the question.
If your teacher then asks why you didn’t answer it, you can safely and unparadoxically claim that inaction is also an option.
If “no answer” is in the set of possible answers, then it is not a correct answer because there’s then a 20% chance of it being picked at random. But usually that’s not the case for tests anyways.
Severe programmer mentality 😂 I like it, but I doubt it would play out in the real world
self-referential paradox
This. I.e., there is no correct answer.
Sooo, C?
if c was correct then it would be 25% then 50% and then 25% again ans 50% and 25%
False
add a e) 20%
Does anyone else smell pancakes?
Yeah, that’s me. They’re ready.
Trick question: One of the 25s is an imposter.
It’s a mimic-dark souls math. If you pick it, the test eats you.
It’s actually 2S with S=12.5
And 50 is 5O, where O=0
Its 25%. The rules of answering a question with a set of options is that you may only choose one and only one is right unless explicitly stated otherwise. Anything else is breaking the rules, which as the taker would be disqualifying. If you start narrowing it down, as in “its 25% and theres two so now i need to guess therefore its 50” you are no longer answering the question at random and you have answered wrong. But you do have to make that coin flip. Good luck.
I’ve never heard that rule. It sounds like an assumption you’re making about the question!
This is the only correct answer to the question as stated.
That of course opens a second can of worms, since now you are actually forced to “pick the answer at random”, now with the probability of 50%. But such double entendres are typically not considered for test questions unless explicitly specified.
Yeah, in my opinion the answer is 50%. You got a 50/50 shot at picking the correct 25% answer.
The right answer is neither a nor b nor c nor d, but “beer with tzatziki”.
Mixed?
Aye.
