Hi! I’m working on an arduino project that has a -12v/0v/+12 psu. +12 is fed directly into arduinos voltage regulator, so there’s also a +5v line available. I need to convert a -5v+5v signal to 0v+5v to feed it into arduinos analogue input and I’ve already mocked up a schematic in circuitjs based on an opamp that seems to do what I want. The only problem is that it needs -5v to shift the signal to be unipolar. I know that I can invert +5v using another opamp, but maybe there’s some simpler way? I’d really like to avoid adding another opamp just for this? In this schematic I used simple voltage divider to get the needed voltage, but I guess that’s not the best approach?
TLDR: I have -12v, 0v, +12v and +5v, what’s the easiest way to get -5v?
Supply the OpAmp with +/-12V or +5/0V and use a non inverting Summing OpAmp Circuit to get your 0-5V signal. V1 is 5V, V2 your input.
thanks! gonna give it a try tomorrow. I’m pretty new to this, and never used opAmps in non-inverting configuration, so I missed this option
Exiting! It has been some time for me too, let me know how you solved the problem at the end.
it worked! (at least in the sim)
thanks a lot!
I’m not sure I got all the math right, since I get 0 - 5.05V on the output, but it’s not a deal breaker for me.
I attached the schematics, but not sure that images in comments federate from kbin to lemmy, so if you don’t see it, try opening an original link to this comment.
ah, a little bit of thinking helped me realize that I don’t need 1k in inverting loop and then I’ll get 5v instead of 5.05v :) and 100k can also be replaced by 1k
So what should happen if you replace the 1k in the inverting loop by 0 Ohm is, you should get a 5V square wave.
Is that correct?
No, with 0 Ohm I get a perfect 0+5v sine, just as I need. It’s the other way round, it’ll amplify the signal and clip off the top at about + supply voltage when you increase the resistance in the feedback loop, but it’s not exactly square wave, as the bottom part of sine will remain intact. I use clipping schottky diodes to protect the arduino from voltage outside 0+5v range, this way if you increase input signal to say 20v peak to peak, you’ll get more square-ish wave in 0+5v (I’ve attached the schematics)
You’re right of course. Two more questions if you don’t mind:
At the moment you’re also mixing up your + input. 10V AC + 5V DC result in 7.5V input in your sim.
I already ordered PCB for the prototype. I hope it’ll work fine. Thanks a lot for your help :)